x^2+826x+11028=0

Solution for x^2+826x+11028=0 equation:

x^2+826x+11028=0

a = 1; b = 826; c = +11028;
Δ = b2-4ac
Δ = 8262-4·1·11028
Δ = 638164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{638164}=\sqrt{4*159541}=\sqrt{4}*\sqrt{159541}=2\sqrt{159541}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(826)-2\sqrt{159541}}{2*1}=\frac{-826-2\sqrt{159541}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(826)+2\sqrt{159541}}{2*1}=\frac{-826+2\sqrt{159541}}{2}
$